In the given figure, which property of congruence can be used to prove that △ABC≅△CDA?
SAS
ASA
RHS
SSS
In △ABC and △CDA,
AC=CA [Common side]
AB=CD [Given]
Also, ∠ACB=∠CAD=90∘ [Given]
Therefore, △ABC≅△CDA [by RHS congruence condition]
In the given figure, which congruence rule can be used to prove that △ABC ≅ △CDA?
In the given figure, if AB = AC and D is the midpoint of BC, then triangle ADB is congruent to triangle ADC by congruency.
In the given figure, BA⊥AC, DE⊥DF, such that, BA=DE, BF=EC. Then, △ABC≅△DEF by which congruence rule?