Question

In the given isosceles triangle, side $BC=14cm$ and side $AB=1\frac{1}{2}l\left(BC\right)$. Find the perimeter of the given triangle

Answer 1

$BC=14cm$

$AB=1\frac{1}{2}BC$

$=\frac{3}{2}\times 14$

$=21cm$

$\therefore AB=AC\left(given\right)$

$=AB=AC=21cm$

$perimeterof\Delta ABC=AB+BC+AC$

$=21+14+21$

$=56cm$