Question

In the given kite ABCD, $\angle ADB={50}^o$ and $\angle BCD={70}^o$

Find$\angle BCO$.

• A. ${35}^o$
• B. ${45}^o$
• C. ${55}^o$
• D. ${75}^o$

Answer 1

Answer: (A)

${35}^o$

Since, the diagonal AC bisects $\angle C$,

$\angle BCO=\frac{1}{2}\times \angle BCD$

$=\frac{1}{2}\times {70}^o$
$={35}^o$