Question

In the given network capacitance $C_2=10\mu F,C_1=5\mu F$ and $C_3=4\mu F.$ The resultant capacitance between $P$ and $Q$ will be:

• A. $4.7\mu F$
• B. $1.2\mu F$
• C. $3.2\mu F$
• D. $2.2\mu F$

Answer 1

The correct option is C $3.2\mu F$

FOR IMAGE 01: The Parallel combination are:

$(10+5=15\mu F)$

FOR IMAGE 02: The series combination are:

$C_s=\frac{15\times 4}{15+4}=\frac{60}{19}=3.2\mu F$