wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

In the given network of capacitors as shown in the figure, given that C1=C2=C3=400 pF and C4=C5=C6=200 pF. The effective capacitance of the circuit between X and Y is.


A
810 pF
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
205 pF
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
600 pF
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
410 pF
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 410 pF
Let us use the technique of succesive reduction.



Here, in thefigure C=(C3+C4)(C2)C3+C4+C2

C=(400+200)×(400)(400+200+400)=(600)(400)1000

C=240 pF

Now, applying the formula and redrawing the circuit,


C′′=(400)(440)840=209.5 pF

Now, C′′ and C6 are in parallel. So, the equivalent capacitance,

Ceq=C′′+C6=209.5+200=409.5 pF410 pF

Hence, option (d) is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Wheatstone Bridge
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon