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Question

In the given quadrilateral ABCD, p+q=100,p and q are supplementary of a and b respectively
a=140 and r=12(a+q) Find the angles p,q and r.

A
p=60,q=40,r=100
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B
p=60,q=100,r=40
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C
p=40,q=60,r=100
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D
p=100,q=60,r=120
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Solution

The correct option is B p=40,q=60,r=100
p+a=180
p+140=180p=40

and given that p+q=100
40+q=100q=60

But b+q=100b+60=180
b=120
given r=1/2(a+q)r=1/2(140+60)
r=100
577885_394852_ans_75de4ccadb004b368dffe29b2da1bebe.png

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