Reversing the 3 Digit Numbers and Subtracting Them
In the given ...
Question
Question 7
In the given question, out of four options, only one is correct. Write the correct answer.
Let abc be a three-digit number. Then, abc + bca + cab is not divisible by (a) a + b + c (b) 3 (c) 37 (d) 9
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Solution
We know that, the sum of three-digit numbers taken in cyclic order can be written as 111(a + b + c) i.e. abc + bca + cab = 3×37×(a+b+c) Hence, the sum is divisible by 3, 37 and (a + b + c) but not divisible by 9.