In the given radioactive disintegration series, 23592U→20782Pb Calculate the difference between the number of α and β particles emitted in this series.
A
3
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B
3.00
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C
3.0
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Solution
23592U→20782Pb
As the mass is reduced from 235 to 207, there must have been 7 α particles released as the mass is reduced by 28.
4 β particles must also have been released as the atomic number reduces only by 10 not by 14.