In the given reaction sequence- CH3C- CH CH4-12Compound 2 will be-

The correct option is C CH_3C≡ CCOOH ...

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Mathematics of Dipole Moment

In the given ...

Question

In the given reaction sequence:
$C H_{3} C \equiv C H C H_{3} M g B r - -------- \to C H_{4} + (1) (i) C O_{2} - --------- \to (i i) H_{2} O / H^{\oplus} (2)$
Compound $(2)$ will be:

C H_{3} C \equiv C C H_{3}

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C H_{3} C \equiv C M g B r

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C H_{3} C \equiv C C O O H

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C H_{3} C H = C H C O O H

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C H_{3} C \equiv C C H_{3} \to C H_{3} C H = C H C H_{3}

{C H}_{3} C \equiv C {C H}_{3}

C H_{3} C \equiv C C H_{3} i) X - --- \to i i) \frac{H_{2} O}{Z n} C H_{3} - C | O - C | O - C H_{3}

C H_{3} C H_{2} C \equiv C H

C H_{3} C \equiv C C H_{3}

C H_{3} C H_{2} C H_{2} C H_{3}

C H_{3} C H = C H_{2}

C H_{3} C \equiv C H H_{2} S O_{4} / H g^{2 +} - ------- \to H_{2} O / 60^{o} A C H_{3} M g C l - ----- \to H_{2} O B

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