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Octet Rule

In the given ...

Question

In the given structure of compound, the correct various bond moments direction involving atoms are shown as:

B r ⟵ - N ⟵ - C H_{2} ⟶ - S i H_{2} ⟵ - H_{2} ⟶ - O ⟵ - C H_{3}

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B r ⟵ - N ⟵ - C H_{2} ⟵ - S i H_{2} ⟵ - C H_{2} ⟶ - O ⟵ - C H_{3}

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B r ⟶ - N ⟵ - C H_{2} ⟵ - S i H_{2} ⟶ - C H_{2} ⟶ - O ⟵ - C H_{3}

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B r ⟵ - N ⟶ - C H_{2} ⟶ - S i H_{2} ⟵ - C H_{2} ⟶ - O ⟶ - C H_{3}

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Solution

The correct option is C $B r ⟶ - N ⟵ - C H_{2} ⟵ - S i H_{2} ⟶ - C H_{2} ⟶ - O ⟵ - C H_{3}$
Bond moments direction depends on the electronegativity of the elements.

The electronegativity of the given elements is-
$O > N > B r > C > S i$

option C is correct.

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C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

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