Question

In the given $△ABC$, AB = 12 cm, BC = 8 cm and AC = 10 cm. Find AF, BD and CE.

Answer 1

In the given figure, let $CE=CF=x$

It is also given that $AB=12$ cm, $BC=8$ cm and $AC=10$ cm, therefore,

$AF=AD=10-x$

$BE=BD=8-x$

Now consider,

$AB=AD+BD\Rightarrow 12=10-x+8-x\Rightarrow 12=18-2x\Rightarrow 2x=18-12\Rightarrow 2x=6\Rightarrow x=\frac{6}{2}=3$

Therefore, $CE=x=3$ cm, $AF=10-3=7$ cm and $BD=8-3=5$ cm

Hence, $CE=3$ cm, $AF=7$ cm and $BD=5$ cm.