In the given triangle $A B C$ , find a point $P$ equidistant from $A B$ and $A C$ ; and also equidistant from $B C$

Open in App

Solution

Every triangle has an in circle and the centre of the circle is equidistant from all the sides.

Suggest Corrections

Similar questions

Construct a triangle ABC, with AB=5.6 cm, AC=BC=9.2 cm.

Find the points equidistant from AB and AC; and also 2 cm from BC.

Measure the distance between the two points obtained.

In triangle ABC, the construction required to find point P equidistant from AB and AC and also, equidistant from B and C is/are

On constructing a triangle ABC, with AB = 5.6 cm, AC = BC = 9.2 cm, the distance between the points which are both equidistant from AB and AC and also 2 cm from BC is

Q. A triangle ABC is constructed with sides AB = 5.6 cm, AC = BC = 9.2 cm. What is the distance between the points which are both equidistant from AB and AC and also 2 cm from BC?

Construct a triangle ABC, in which $A B C = 75^{o}$ ,AB=5 cm and BC=6.4 cm. Draw perpendicular bisector of side BC and also the bisector of Angle ACB.If these bisectors intersect each other at point P;prove that P is equidistant from B and C; and also from AC and BC.

Join BYJU'S Learning Program

In the given triangle ABC, find a point P equidistant from AB and AC; and also equidistant from BC

Every triangle has an in circle and the centre of the circle is equidistant from all the sides.

In the given triangle $A B C$ , find a point $P$ equidistant from $A B$ and $A C$ ; and also equidistant from $B C$