In the given triangle ABC, the point P is the intersection of all the medians. The length of AE is 24 cm. Then what is the length of AP?

8 cm

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10 cm

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12 cm

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16 cm

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Solution

The correct option is D
16 cm

The point of intersection of all the medians is called the centroid and it divides each median is in the ratio of 2 : 1.
So, AP : PE =2 : 1
Here, AE=24 cm

So, $A P = \frac{2}{3} \times 24 = 16 c m$

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In the given triangle ABC, the point P is the intersection of all the medians. The length of AE is 24 cm. Then what is the length of AP?

The correct option is D 16 cm The point of intersection of all the medians is called the centroid and it divides each median is in the ratio of 2 : 1. So, AP : PE =2 : 1 Here, AE=24 cm So, AP = 23×24 = 16 cm

The correct option is D
16 cm

The point of intersection of all the medians is called the centroid and it divides each median is in the ratio of 2 : 1.
So, AP : PE =2 : 1
Here, AE=24 cm

So, $A P = \frac{2}{3} \times 24 = 16 c m$