In the given (V-T) diagram, what is the relation between pressures $P_{1}$ and $P_{2}$ ?

P_{2} = P_{1}

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P_{2} > P_{1}

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P_{2} < P_{1}

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Cannot be predicted

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Solution

The correct option is C $P_{2} < P_{1}$
Since PV = nRT
$\frac{V}{T} = \frac{n R}{P}$
Slope of the graph $\propto \frac{1}{P r e s s u r e}$ so it evdent from the graph that $P_{2}$ will be smaller as compared to $P_{1}$ .

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The pressure $P_{1}$ at a certain depth in river water and $P_{2}$ at the same depth in sea water are related as :
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V verus T curves at constant pressures $P_{1}$ and $P_{2}$ for an idealgas are shown in the figure,

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In the given (V-T) diagram, what is the relation between pressures P1 and P2?

The correct option is C P2<P1Since PV = nRTVT=nRPSlope of the graph ∝1Pressure so it evdent from the graph that P2 will be smaller as compared to P1.

In the given (V-T) diagram, what is the relation between pressures $P_{1}$ and $P_{2}$ ?

The correct option is C $P_{2} < P_{1}$
Since PV = nRT
$\frac{V}{T} = \frac{n R}{P}$
Slope of the graph $\propto \frac{1}{P r e s s u r e}$ so it evdent from the graph that $P_{2}$ will be smaller as compared to $P_{1}$ .