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Question

# In the ground state electronic configuration of Mn (Z=25):

A

the number of electrons having n+l = 4 are 5

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B
the number of electrons having m=0 are 13
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C

the electron is first filled in 3d then in 4s subshell

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D

the number of electrons having l=1 are 10

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Solution

## The correct option is B the number of electrons having m=0 are 13Ground state electronic configuration for Mn is: Mn=1s22s22p63s23p63d54s2 Now let’s check n+l value for each subshell involved i.e 1s⇒1+0=1 2s⇒2+0=2 2p⇒2+1=3 3s⇒3+0=3 3p⇒3+1=4 3d⇒3+2=5 4s⇒4+0=4 So there are two cases for which n+l=4 i.e. 3p and 4s. Hence, total no of electrons are 8. So (a) option is incorrect. m will be zero for electrons in all s subshell, one orbital each in each p subshell and d subshell. For Mn, total number of electrons having m = 0 is 13. Hence (b) option is correct. In ground state electron is first filled in 4s than in 3d because 4s is of lower energy than 3d as per (n+l) rule. Hence (c) is incorrect. The electrons having l=1 (p subshell) are 12. Hence (d) option is incorrect.

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