In the Hall effect, we have a current flowing in the presence of a uniform magnetic field, and we get a potential difference across the conductor. Which is(are) incorrect statement(s)?

A changing magnetic field produces an induced EMF.

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Charges are bent from their paths until an electric field is built up transverse to the wire to stop them from bending.

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The charges in the wire are moving, so the electric fields are changing with time.

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The charges produced by the current repel each other and produce a build up of charge on the surface of the conductor.

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Solution

The correct option is D The charges produced by the current repel each other and produce a build up of charge on the surface of the conductor.
As magnetic field is uniform, therefore, there will be no induced EMF.

In the above figure, the dashed line shows the path of the charges.

Charges are bent from their paths until an electric field is built up transverse to the wire to stop them from bending.

Initially, $F_{m} > F_{e}$ , therefore, charges will move with curved path.

When $F_{e}$ become equal to $F_{m}$ due to more accumulation of negative charges on the other side, charges will move straight, and electric field will be constant.

The build up of charge on the surface of the conductor is due to the magnetic force on it.

Hence, statements in the options $A, C$ and $D$ are incorrect.

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