In the ionic equation 2K-Br O -3-12H-10e- Br2-6H2O-2K- the equivalent weight of KBrO3 will be-Where M - molecular weight of KBrO3

The correct option is A M/5 2K_ #160; ^ + + BrO _ 3 ^ + 12H ^ + + 10e ^ ⟶ Br _ 2 + 6H _ 2 O+2K^ + +5 BrO _ 3 ^ ⟶ 0 Br _ ...

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In the ionic ...

Question

In the ionic equation $2 K^{+} B r O_{3}^{-} + 12 H^{+} + 10 e^{-} \to B r_{2} + 6 H_{2} O + 2 K^{+}$ , the equivalent weight of $K B r O_{3}$ will be:(Where M $=$ molecular weight of $K B r O_{3}$ )

M / 5

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M / 2

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M / 6

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M / 4

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Solution

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Similar questions

2 K^{+} + B r O^{3 -} + 12 H^{+} + 10 e^{-} \to B r_{2} + 6 H_{2} O + 2 K

K B r O_{3}

K B r O_{3}

2 B r O_{3}^{-} + 12 H^{+} + 10 e^{-} \to B r_{2} + 6 H_{2} O

K B r O_{3}

M

K B r O_{3}

M

B r O_{3}^{-} \to B r^{-} (a c i d i c m e d i u m)

3 B r_{2} + 6 O H^{⊖} \to 5 B r^{⊖} + B r O_{3}^{⊖} + 3 H_{2} O

B r_{2}

M

For the reaction

$3 {B r}_{2}$ + $6 {O H}^{Θ}$ $\to$ $5 {B r}^{Θ}$ + $B r {O_{3}}^{Θ}$ + $3 H_{2} O$

Equivalent weight of ${B r}_{2}$ (Molecular weight M) is

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