MyQuestionIcon

7

You visited us 7 times! Enjoying our articles? Unlock Full Access!

Zinc Ion

In the Lassai...

Question

In the Lassaigne's test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of ?

A

N a_{4} [F e (C N)_{6}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

F e_{4} [F e (C N)_{6}]_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

F e_{2} [F e (C N)_{6}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

F e_{3} [F e (C N)_{6}]_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $F e_{4} [F e (C N)_{6}]_{3}$
Reaction of process:
$F e^{3 +} + [F e C N)_{6}]^{4 -} ⟶ F e_{4} [F e (C N)_{6}]_{3}$
Prussian blue
(Ferri-ferrocyanide)

Suggest Corrections

thumbs-up

0

Similar questions

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) Na₄[Fe(CN)₆] (b) Fe₄[Fe(CN)₆]₃ (c) Fe₂[Fe(CN)₆] (d) Fe₃[Fe(CN)₆]₄

Q. In the Lassaigne's test for the nitrogen in an organic compound, the Prussian colour is obtained due to the formation of :

{F e}^{2 +}

gives blue colour, called Turnbull's blue with

K_{3} [{F e (C N)}_{6}]

{F e}^{3 +}

gives blue colour, called Prussian blue with

K_{4} [{F e (C N)}_{6}]

If the given statement is true enter 1 else enter 0.

{N H}_{2} - {N H}_{2}

gives Prussian blue colour during Lassaigne test (element detection test). Reason: NaCN gives Prussian blue colour of

{F e}_{4} {[F e ({C N}_{6})]}_{3}

F e {S o}_{4}, F e {C I}_{3}

.

Q. In the Lassaignes test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Zinc ion

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard X Chemistry

Join BYJU'S Learning Program

CrossIcon