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Zinc Ion

In the Lassai...

Question

In the Lassaigne's test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of ?

A

N a_{4} [F e (C N)_{6}]

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B

F e_{4} [F e (C N)_{6}]_{3}

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C

F e_{2} [F e (C N)_{6}]

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D

F e_{3} [F e (C N)_{6}]_{4}

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Solution

The correct option is A $F e_{4} [F e (C N)_{6}]_{3}$
Reaction of process:
$F e^{3 +} + [F e C N)_{6}]^{4 -} ⟶ F e_{4} [F e (C N)_{6}]_{3}$
Prussian blue
(Ferri-ferrocyanide)

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In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) Na₄[Fe(CN)₆] (b) Fe₄[Fe(CN)₆]₃ (c) Fe₂[Fe(CN)₆] (d) Fe₃[Fe(CN)₆]₄

Q. In the Lassaigne's test for the nitrogen in an organic compound, the Prussian colour is obtained due to the formation of :

{F e}^{2 +}

gives blue colour, called Turnbull's blue with

K_{3} [{F e (C N)}_{6}]

{F e}^{3 +}

gives blue colour, called Prussian blue with

K_{4} [{F e (C N)}_{6}]

If the given statement is true enter 1 else enter 0.

{N H}_{2} - {N H}_{2}

gives Prussian blue colour during Lassaigne test (element detection test). Reason: NaCN gives Prussian blue colour of

{F e}_{4} {[F e ({C N}_{6})]}_{3}

F e {S o}_{4}, F e {C I}_{3}

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Q. In the Lassaignes test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

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