Question

In the lowest energy level of hydrogen atom, the electron has the angular orbital momentum of -

• A. $\frac{\pi }{h}$
• B. $\frac{h}{\pi }$
• C. $\frac{h}{2\pi }$
• D. $\frac{2\pi }{h}$

Answer 1

The correct option is C $\frac{h}{2\pi }$

We know that,

$L_n=mv{r}_n=\frac{nh}{2\pi }$

For lowest energy level, $n=1$.

$\therefore L=\frac{h}{2\pi }$

Hence, option $\left(C\right)$ is the correct answer.