Question

In the molecule $S{F}_6$, the number of F-S-F bonds that make 180${}^{\circ }$ is/are:

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is C 3


$\angle F^1-S-F^2={180}^o$
$\angle F^3-S-F^5={180}^o$
$\angle F^4-S-F^6={180}^o$