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Question

In the preparation of CaO from CaCO3 using the equilibrium CaCO3(s)CaO(s)+CO2(g) Kp is expressed as:

logKp=7.2828500T
for complete decomposition of CaCO3 the temperature in celsius to be used is:

A
1167
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B
894
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C
8500
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D
850
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Solution

The correct option is B 894
In the preparation of CaO from CaCO3 using the equilibrium
CaCO3(s)CaO(s)+CO2(g)
Kp is expressed as:
logKp=7.2828500T
for complete decomposition of CaCO3 the temperature in celsius to be used is 894.
For complete decomposition of CaCO3
Kp=1
logKp=log1=0
logKp=7.2828500T
0=7.2828500T
7.282=8500T
T=1167 K
T=1167273=894oC.

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