In the preparation of chloroform from ethyl alcohol and bleaching powder, the compound that is not formed is :

acetaldehyde.

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chloral.

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phosgene.

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trichloro acetaldehyde.

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Solution

The correct option is C phosgene.
Following reactions are involved in the preparation of chloroform:
$C a O C l_{2} + H_{2} O \to C a (O H)_{2} + C l_{2}$
Then from alcohol,
$C H_{3} C H_{2} O H + C l_{2} - 2 H C l - --- \to C H_{3} C H O a c e t a l d e h y d e + 2 H C l$

$C H_{3} C H O + 3 C l_{2} \to C C l_{3} C H O C h l o r o l o r T r i c h l o r o a c e t a l d e h y d e + 3 H C l$ (chlorination)

$2 C C l_{3} C H O + C a (O H)_{2} \to 2 C H C l_{3} C h l o r o f o r m$ (hydrolysis)
Phosgene $(C O C l_{2})$ doesn't form in the whole process.

Hence, the correct option is C.

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