Question

In the preparation of copper sulfate from copper,oxidation state of oxidising agent changes from:

• A. $+4$ to $+2$
• B. $+6$ to $+2$
• C. $+6$ to $+4$
• D. $+6$ to $0$

Answer 1

Answer: (C)

$+6$ to $+4$

$Cu\left(g\right)+H_{2}S{O}_4\left(l\right)\to CuS{O}_4\left(aq\right)+S{O}_2\left(g\right)+2H_{2}O\left(l\right)$

In the preparation of copper sulfate from copper,oxidation state of oxidising agent changes from $+6$ to $+4$. $(H_{2}S{O}_4$ to $S{O}_2$)