In the presence of acid, the initial concentration of cane-sugar was reduced from 0.2 M to 0.1 in 5 hr and to 0.05 M in 10 hr. The order of reaction is

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Solution

$0.2 M \to t_{1 / 2} = 5 h r 0.1 M \to t_{1 / 2} = 5 h r 0.05 M$
$F r o m 0.2 M \to t = 10 h r 0.05 M$
So $t_{1 / 2}$ is constant which is characteristic of first order reaction.
Hence, $t_{1 / 2} \propto (a)^{0}$ .

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In the presence of acid, the initial concentration of cane-sugar was reduced from 0.2 M to 0.1 in 5 hr and to 0.05 M in 10 hr. The order of reaction is

0.2M→t1/2=5hr0.1M→t1/2=5hr0.05MFrom0.2M→t=10hr0.05MSo t1/2 is constant which is characteristic of first order reaction.Hence, t1/2∝(a)0.

$0.2 M \to t_{1 / 2} = 5 h r 0.1 M \to t_{1 / 2} = 5 h r 0.05 M$
$F r o m 0.2 M \to t = 10 h r 0.05 M$
So $t_{1 / 2}$ is constant which is characteristic of first order reaction.
Hence, $t_{1 / 2} \propto (a)^{0}$ .