Question

In the pressure-volume diagram given below, the isochoric, isothermal, isobaric and isoentropic parts respectively are:

• A. $BA,AD,DC,CB$
• B. $DC,CB,BA,AD$
• C. $AB,BC,CD,DA$
• D. $CD,DA,AB,BC$

Answer 1

The correct option is B $DC,CB,BA,AD$

For process $DC$, $\Delta V=0$.

Therefore, $DC$ is an isochoric process.

For process $AB$, $\Delta P=0$.

Therefore, $AB$ is an isobaric process.

Process $BC$ is isothermal, i.e., $\Delta T=0$.

Process $AD$ is isoentropic, i.e., $\Delta S=0$.