Question

In the pulley system shown, if radii of the bigger and smaller pulley are 2 m and 1 m, respectively and the acceleration of block A is $5m/s^{-2}$ in the downward direction, the acceleration of block B will be :

• A. $0m{s}^{-2}$
• B. $5m{s}^{-2}$
• C. $10m{s}^{-2}$
• D. $\frac{5}{2}m{s}^{-2}$

Answer 1

Answer: (D)

$\frac{5}{2}m{s}^{-2}$

Using the relation $a=r\alpha$ we have
$a=2\alpha =5m/s^2$
Thus $\alpha =\frac{5}{2}m/s^2$
Thus acceleration of block B will be
$\alpha =1\alpha =\frac{5}{2}m/s^2$