In the reaction- 2FeS O 4 - H 2 S O 4 - H 2 O 2 - Fe 2 S O 4 3 -2 H 2 O- the oxidizing agent is -

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Preparation of Nitric Acid

In the reacti...

Question

In the reaction, $2 F e S O_{4} + H_{2} S O_{4} + H_{2} O_{2} \to {F e}_{2} {(S O_{4})}_{3} + 2 H_{2} O$ , the oxidizing agent is :

F e S O_{4}

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H_{2} S O_{4}

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H_{2} O_{2}

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both

H_{2} S O_{4}

and

H_{2} O_{2}

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Solution

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In reaction

$S O_{2}$ + $H_{2} S$ $\to$ $2 H_{2} O$ + $3 S$

the reducing agent is –

H_{2} O_{2}

H_{2} O_{2}

- 1

C u + H_{2} S O_{4} \to C u S O_{4} + {S O}_{2} ↑ + H_{2} O

F e + H_{2} O \to {F e}_{3} O_{4} + H_{2} ↑

{C H}_{4} + O_{2} \to C O_{2} + H_{2} O

{A g}_{2} O + H_{2} O_{2} ⟶ 2 A g + H_{2} O + O_{2}

H_{2} O_{2}

(i) Mn O_{2} + 4HCl \to MnC l_{2} + 2 H_{2} O + C l_{2}

(i i) CuO + H_{2} \to Cu + H_{2} O

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