Question

In the reaction $2Mg+C{O}_2\to 2MgO+C$, oxidizing and reducing agents are, respectively,_______ and ___________.

Answer 1

1.In the reaction, $2Mg+C{O}_2\to 2MgO+C$, $Mg$ is in its $0$oxidation state and $C$ shows $+4$oxidation state in $C{O}_2$molecule before the reaction.

2.After the reaction, $Mg$ loses $2e^{-}$ and forms $M{g}^{+2}$ in $MgO$ and $C$ reaches to $0$ oxidation state by gaining electrons.

Since, Mg is undergoing oxidation it is a reducing agent and C is undergoing reduction it is an oxidizing agent.

Thus, In the reaction $2Mg+C{O}_2\to 2MgO+C$, oxidizing and reducing agents are, respectively, C and Mg