In the reaction 2Na2S2O3 - I2 - Na2S4O6 - 2 NaI- the oxidation state of sulphur is -

The correct option is C increasedGiven the reaction: 2Na_2S_2O_3 + I_2 → Na_2S_4O_6 + 2 NaI #160; #160; #160; #160; #160;+2 #160; #160 ...

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Oxides of Sulphur

In the reacti...

Question

In the reaction $2 N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I$ , the oxidation state of sulphur is :

decreased

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increased

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unchanged

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none of these

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Solution

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2 N a_{2} S_{2} O_{3} + I_{2} = N a_{2} S_{4} O_{6} + 2 N a I, I_{2}

I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

2 N a_{2} S_{2} O_{3} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}

N a_{2} S_{2} O_{3}

2 N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I

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