Question

In the reaction $2P\left(g\right)+Q\left(g\right)\rightleftharpoons 3R\left(g\right)+S\left(g\right)$. If 2 moles each of $P$ and $Q$ is taken initially in a 1 litre flask. At equilibrium which of the following is true?

• A. $\left[P\right]<\left[Q\right]$
• B. $\left[P\right]=\left[Q\right]$
• C. $\left[Q\right]=\left[R\right]$
• D. None of these

Answer 1

The correct option is A $\left[P\right]<\left[Q\right]$

$2P\left(g\right)+Q\left(g\right)\rightleftharpoons 3R\left(g\right)+S\left(g\right)$

Initial	$2$	$2$	$0$	$0$
Final	$2-2x$	$2-x$	$3x$	$x$

At equilibrium:

$P=2-2x$ mole and $Q=2-x$ moles

So, $\left[Q\right]>\left[P\right]$