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Question

In the reaction, 2S2O23+I2S4O26+2I, the equivalent weight of Na2S2O3 is equal to its.

A
Molecular wt.
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B
12× Molecular wt.
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C
2× Molecular wt.
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D
16× Molecular wt..
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Solution

The correct option is B Molecular wt.
According to reaction,

2S2O23+I2S4O26+2I

Oxidation of S in S2O23=2
Oxidation number of S in S4O26=52

Again, 2S2O23S4O26

For 2 moles of S2O23 change in oxidation number
=4×522×2×2
=2

For 1 mol =22=1

Equivalent mass of Na2S2O3=Molecular wtChange in oxidation no.

=Molecular wt1
option A is correct

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