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Byju's Answer
Standard XII
Chemistry
Reaction with Metals
In the reacti...
Question
In the reaction,
2
S
2
O
2
−
3
+
I
2
⟶
S
4
O
2
−
6
+
2
I
−
, the equivalent weight of
N
a
2
S
2
O
3
is equal to its.
A
Molecular wt.
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B
1
2
×
Molecular wt.
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C
2
×
Molecular wt.
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D
1
6
×
Molecular wt..
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Solution
The correct option is
B
Molecular wt.
According to reaction,
2
S
2
O
2
−
3
+
I
2
→
S
4
O
2
−
6
+
2
I
−
Oxidation of
S
in
S
2
O
2
−
3
=
2
Oxidation number of
S
in
S
4
O
2
−
6
=
5
2
Again,
2
S
2
O
−
2
3
→
S
4
O
−
2
6
For 2 moles of
S
2
O
−
2
3
change in oxidation number
=
4
×
5
2
−
2
×
2
×
2
=
2
For 1 mol
=
2
2
=
1
∴
Equivalent mass of
N
a
2
S
2
O
3
=
Molecular wt
Change in oxidation no.
=
Molecular wt
1
∴
option A is correct
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Similar questions
Q.
In the reaction,
I
2
+
2
S
2
O
2
−
3
→
2
I
−
+
S
4
O
2
−
6
equivalent weight of iodine is
Q.
In the reaction
I
2
+
2
S
2
O
−
−
3
→
2
I
−
+
S
4
O
−
−
6
equivalent weight of iodine will be equal to
Q.
In the reaction,
I
2
+
2
S
2
O
2
−
3
→
2
I
−
+
S
4
O
2
−
6
equivalent weight of iodine will be equal to
Q.
The equivalent weight of
N
a
2
S
2
O
3
(Mol. wt . = M ) in the reaction,
2
N
a
2
S
2
O
3
+
I
2
→
N
a
2
S
4
O
6
+
2
N
a
I
is :
Q.
In the reaction,
I
2
+
2
S
2
O
2
−
3
→
2
I
−
+
S
4
O
2
−
6
equivalent weight of iodine is
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