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Gibbs Free Energy & Spontaneity

In the reacti...

Question

In the reaction $A^{+} + B \to A + B^{+},$ there is no entropy change. If enthalpy change is $22 k J / m o l$ , calculate $△ G$ for the reaction.

25 k J m o l^{- 1}

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28 k J m o l^{- 1}

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22 k J m o l^{- 1}

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20 k J m o l^{- 1}

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Solution

The correct option is C $22 k J m o l^{- 1}$
For the given reaction, $A^{+} + B \to A + B^{+}$
$△ H = 22 k J / m o l, △ S = 0$
$∴ u s i n g, △ G = △ H - T △ S$
$△ G = 22 - T \times 0 = 22 k J m o l^{- 1}$
Hence, $△ G$ for the reaction is $22 k J m o l^{- 1}$

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