Question

In the reaction $A+B\rightleftharpoons C+D$, the value of equilibrium constant is 10. If the rate constant of forward reaction is 80, the rate constant of backward reaction is :

• A. $1/8$
• B. $8$
• C. $800$
• D. None of these

Answer 1

Answer: (B)

$8$

As we know,
$(K_{eq}=\frac{K_f}{K_b}\therefore K_b=\frac{K_f}{K_{eq}}=\frac{80}{10}=8)$