Question

In the reaction $A\to B$, if the concentration of $A$ is increased by four times the rate of reaction is doubled, the order of the reaction is:

• A. 0
• B. 1
• C. 2
• D. 0.5

Answer 1

The correct option is D 0.5

$rate=k[C\times A{]}^x$.

$2\times r=k[4\times A{]}^x$.

devide 1 by 2.

$\frac{1}{2}=\frac{1}{4x}$.

$2x=1$.

$x=\frac{1}{2}$.

$X=0.5$.

Hence option D is correct.