In the reaction, $A l {C l}_{3} + {C l}^{-} = A l {C l}_{4}^{-}$ .
$A l {C l}_{3}$ can be classified as:

A base

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An acid

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A salt

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none of these

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Solution

The correct option is A An acid
$A l C l_{3}$ accepts a lone pair of electrons to complete its octet and form $A l C l_{4}^{-}$ ion so it can be classified as an acid.

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Similar questions

A l C l_{3} + C l^{-} \to A l C l_{4}^{-}, A l C l_{3}

A l C l_{3} + C l^{-} \to [A l C l_{4}]^{-}, A l C l_{3}

A l

A l C l_{3} + C l^{-} \to A l C l_{4}^{-}

A l

A l C l_{3} + C l^{-} \to {A l C l_{4}}^{-}

A l {C l}_{3} + {C l}^{-} ⟶ {[A l {C l}_{4}]}^{-}

A l {C l}_{3}

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