In the reaction, $A l {C l}_{3} + {C l}^{-} ⟶ {[A l {C l}_{4}]}^{-}$ , $A l {C l}_{3}$ acts as a

salt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Lewis base

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Lewis acid

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Bronsted acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Lewis acid
According to Lewis Theory of Acids and Bases, acids are electron pair (lone pair) acceptors and bases are electron pair (lone pair) donors.

For example, in the following reaction:

$N H_{3} + B F_{3} \to N H_{3} \to B F_{3}$

$N H_{3}$ donates its electron pair (lone pair) to $B F_{3}$ .

Hence, $N H_{3}$ is a Lewis Base whereas $B F_{3}$ is a Lewis Acid.

In the given example, $A l C l_{3}$ accepts an electron pair (lone pair) from $C l^{-}$ .

Therefore, $A l C l_{3}$ is a Lewis Acid.

Suggest Corrections

Similar questions

A l C l_{3} + C l^{-} \to [A l C l_{4}]^{-}, A l C l_{3}

A l C l_{3} + C l^{-} \to A l C l_{4}^{-}, A l C l_{3}

A l

A l C l_{3} + C l^{-} \to {A l C l_{4}}^{-}

Describe the change in hybridisation (if any) of the Al atom in the following reaction.

$A l C l_{3} + C l^{-} \to A l C l_{4}^{-}$

Join BYJU'S Learning Program