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Question

In the reaction ,BaCO3 to BaO +CO2 where BaCO3 is 9.5g

Here,will the no. of moles CO2 released is equal to the no.of moles of BaCO3??? If yes,how?

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Solution

Yes your assumption is correct.
BaCO3 -> BaO + CO2
According to the equation 1 mole of BaCO3 will give 1mole of CO2

molecular mass of BaCO3 = 197g
so 197g of BaCO3 will give 1mole(22.4 L) of CO2

-> 9.5g of BaCO3 will give (22.4*9.5)/197 =1.08 L of CO2 at S.T.P

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