Question

In the reaction between $C{l}_2$ and hot conc. NaOH, which is correct?

• A. The oxidation number of $C{l}_2$ changes from 0 to +5 and 0 to -1.
• B. $C{l}_2$ undergoes disproportionation.
• C. $C{l}_2$ undergoes self or auto redox change.
• D. All of these.

Answer 1

The correct option is D All of these.

With hot concentrated alkali solutions it forms chlorates.

$6NaOH+3C{l}_2\to 5NaCl+NaCl{O}_3+3H_{2}O$
0 -1 +5

$C{l}_2$ undergoes disproportionation.

Hence,option D is correct.