Question

When $C{l}_2$ reacts with aqueous NaOH in cold condition then oxidation number of chlorine changes from $0$ to.

• A. $-1$
• B. $+1$
• C. $-2$
• D. $+2$

Answer 1

Answer: (A), (B)

The correct options are
A $-1$
B $+1$

${Cl}_2+2NaOH\to NaCl+NaOCl+H_{2}O$

In reactant $Cl$ is present in $\left(0\right)$ oxidation state and in $NaCl$, it is present in $(-1)$ oxidation state and in $NaOCl$ it is present in (+1) oxidation state.