Question

In the reaction,
$Cu+H_{2}S{O}_4\to CuS{O}_4+H_{2}O+S{O}_2$

• A. $H^{+}$ is an oxidation agent
• B. $S{O}_4^{2-}$ is an oxidising agent
• C. Both (a) and (b) correct
• D. None of these

Answer 1

The correct option is B $S{O}_4^{2-}$ is an oxidising agent

The balance equation is :
$\stackrel{0}{C}u+2H_2\stackrel{+6}{S}{O}_4\to \stackrel{+2}{C}uS{O}_4+2H_{2}O+\stackrel{+4}{S}{O}_2$

Cu is oxidised from 0 oxidation state to +2 oxidation satate by $S{O}_4^{2-}$. Hence $S{O}_4^{2-}$ is an oxidising agent.