In the reaction- H3PO4-2NaOH- Na2HPO4 The equivalent weight of H3 PO4 is-

The correct option is B molecular weight2 Only 2 acidic H^+ ions #160;are involved in the reaction. #160;Therefore, Equivalent weight = ...

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Equivalent Mass

In the reacti...

Question

In the reaction:

$H_{3} P O_{4} + 2 N a O H \to N a_{2} H P O_{4}$

The equivalent weight of $H_{3} P O_{4}$ is:

\frac{m o l e c u l a r w e i g h t}{1}

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\frac{m o l e c u l a r w e i g h t}{2}

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\frac{m o l e c u l a r w e i g h t}{3}

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\frac{m o l e c u l a r w e i g h t}{4}

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Solution

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Similar questions

H_{3} P O_{2} = \frac{m o l e c u l a r w e i g h t}{1}

H_{3} P O_{3} = \frac{m o l e c u l a r w e i g h t}{2}

H_{3} P O_{4} = \frac{m o l e c u l a r w e i g h t}{3}

2 {N H}_{3} ⟶ N_{2} + 2 {N H}_{3}

{N H}_{3}

= \frac{M o l e c u l a r w e i g h t}{y}

y

N H_{3}

N_{2} \to N H_{3}

N_{2}

= \frac{Molecular weight}{Number of electrons lost or gained per molecule}

= \frac{M o l e c u l a r w e i g h t}{A c i d i t y}

N a_{2} S_{2} O_{3}

K_{2} C r_{2} O_{7}

K_{2} C r_{2} O_{7}

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