Question

In the reaction, $I_2+2{S_2{O}_3}^{2-}\to 2I^{-}+{S_4{O}_6}^{2-}$, equivalent mass of iodine is:

• A. equal to its molecular mass
• B. $1/2$ the molecular mass
• C. $1/4$ the molecular mass
• D. twice the molecular mass

Answer 1

Answer: (B)

$1/2$ the molecular mass

From $I_2\to 2I^{-}$

no. of lectron change = 1

n factor = electron change $\ast$ no. of atom = 2 $\ast$= 2

equivalent mass = $\frac{molecularmass}{nfactor}$

so, equivalent mass = $\frac{molecularmass}{2}$