In the reaction I 2-2 S 2 O 3- 2 I - S 4 O 6-equivalent weight of iodine will be equal toA- 1-2 of molecular weightB- 1-4 of molecular weightC- Molecular weightD- None

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Balancing Redox Equations

In the reacti...

Question

In the reaction $I_{2} + 2 S_{2} O_{3}^{- -} \to 2 I^{-} + S_{4} O_{6}^{- -}$ equivalent weight of iodine will be equal to

\frac{1}{2}

of molecular weight

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Molecular weight

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\frac{1}{4}

of molecular weight

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None

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Solution

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Similar questions

I_{2} + 2 S_{2} O_{3}^{2 -} \to 2 I^{-} + S_{4} O_{6}^{2 -}

K M n O_{4}

I_{2} + 2 S_{2} O_{3}^{- -} \to 2 I^{-} + S_{4} O_{6}^{- -}

I_{2} + 2 S_{2} O_{3}^{2 -} \to 2 I^{-} + S_{4} O_{6}^{2 -}

I_{2} + 2 S_{2} O_{3}^{2 -} \to S_{4} O_{6}^{2 -} + 2 I^{-}

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