In the reaction, $I_{2} + I^{-} ⟶ I_{3}^{-}$ the Lewis base is

I_{2}

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I^{-}

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I_{3}^{-}

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N o n e

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Solution

The correct option is C $I^{-}$
Lewis base is an substance which donates a lone pair of electrons so here $I^{-}$ acts as lewis base which donates a lone pair of electrons to $I_{2}$ .

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Similar questions

I_{2} + I^{-} \to I_{3}^{-}

I_{2} + I^{-} \to I_{3}^{-}

I_{2} + I^{-} ⟶ I_{3}^{-}

I_{2}

I_{3}^{-}

I_{2} + I^{-} \to I_{3}^{-}

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