In the reaction $I_{2} + I^{-} \to I_{3}^{-}$ , the Lewis base is

I_{2}

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I^{-}

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I_{3}^{-}

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None

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Solution

The correct option is B $I^{-}$
$I^{-}$ donates electron pair, it is lewis base

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Similar questions

I_{2} + I^{-} \to I_{3}^{-}

I_{2} + I^{-} \to I_{3}^{-}

I_{2} + I^{-} ⇌ I_{3}^{-},

I_{2} + I^{-} ⟶ I_{3}^{-}

I_{2} + I^{-} ⟶ I_{3}^{-}

I_{2}

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