In the reaction $N_{2} + {3 H}_{2} ⟶ {2 H}_{3}$ , ratio by volume of $N_{2}, H_{2}$ and ${N H}_{3}$ is $1 : 3 : 2$ . This illustrates law of :

definite proportions

No worries! We‘ve got your back. Try BYJU‘S free classes today!

multiple proportions

No worries! We‘ve got your back. Try BYJU‘S free classes today!

reciprocal proportions

No worries! We‘ve got your back. Try BYJU‘S free classes today!

gaseous proportions

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C gaseous proportions
As per the Gay Lussac's law of combining volume of gases, the volumes of gaseous reactants and gaseous products bear a simple whole number ratio with each other if they are measured at same temperature and pressure.
In the reaction $N_{2} + {3 H}_{2} ⟶ {2 H}_{3}$ , ratio by volume of $N_{2}, H_{2}$ and $N H_{3}$ is $1 : 3 : 2$ . This illustrates law of Gay Lussac's law of combining volumes of gases.

Suggest Corrections

Similar questions

N_{2} + 3 H_{2} \to 2 N H_{3}

N_{2}, H_{2}

N H_{3}

1 : 3 : 2

At 298K 1 atm, 1 volume of N₂ reacts with 3 volumes of H₂ to give 2 volumes of NH₃. The ratio 1:3:2 illustrates:

N_{2} + 3 H_{2} \to 2 N H_{3}

At 298K 1 atm, 1 volume of N₂ reacts with 3 volumes of H₂ to give 2 volumes of NH₃. The ratio 1:3:2 illustrates:

The equilibrium constant $K_{p}$ for the reaction $N_{2}$ (g) + 3 $H_{2}$ (g) $⇋$ $2 N H_{3}$ (g) is:

Join BYJU'S Learning Program