In the reaction : S + 3/2 O2→SO3 + 2x kcal and SO2+1/2O2→SO3 + y kcal, heat of formation of SO2 is:
A
(x + y)
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B
(x - y)
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C
(2x + y)
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D
(2x - y)
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Solution
The correct option is D (2x - y) S+3/2O2→SO3+2xkcal (i) SO2+1/2O2→SO3+ykcal (ii) Now, subtract eq. (ii) from (i), we get, S+O2→SO2+2x−ykcal ∴ Heat of formation of SO2 is equal to 2x−y kcal.