In the reaction the enthalpy change KOH(aq)+HBr(aq)→KBr(aq)+H2O(l); ΔH298K=−13.7K.cal is referred as_______.
A
heat of reaction
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B
heat of formation
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C
heat of neutralisation
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D
heat of hydration
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Solution
The correct option is D heat of neutralisation KOH(aq) is a base. HBr(aq) is an acid for the reaction of acid & base ΔH= is referred to as heat of neutralisation.