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Byju's Answer
Standard XII
Physics
Resonance in RLC Circuit
In the series...
Question
In the series
L
C
R
circuit shown, the readings of voltmeter and ammeter respectively are
A
V
=
100
V
;
I
=
2
A
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B
V
=
300
V
;
I
=
1
A
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C
V
=
1000
V
;
I
=
2
A
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D
V
=
100
V
;
I
=
5
A
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Solution
The correct option is
A
V
=
100
V
;
I
=
2
A
Clearly ,
V
L
−
V
C
=
0
⇒
The circuit is in Resonance.
∴
Impedance of the circuit,
Z
=
R
=
50
Ω
Now, the reading of voltmeter
V
s
o
u
r
c
e
=
√
V
2
R
+
(
V
L
−
V
C
)
2
V
s
o
u
r
c
e
=
√
V
2
+
(
400
−
400
)
2
⇒
V
=
V
s
o
u
r
c
e
=
100
V
According to ohm's Law:
Δ
V
=
i
R
⇒
i
=
Δ
V
R
=
100
50
=
2
A
Hence, option
(
A
)
is correct.
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