In the Solvay process for producing sodium carbonate Na2 CO3- the following reactions occur in sequence-NH3 - CO2 - H2 O - NH4 HCO3NH4 HCO3 - NaCl - NH4 Cl - NaHCO32NaHCO3 Na2 CO3 - H2 O - CO2How much of Na2 CO3 would be produced per kg of NH3 used if the process were 100

Based on stoichiometry, 1 mol Na_2 CO_3 is obtained from 2 mol NH_3 106 g Na_2 CO_3 is from = 2 × 17 g NH_3 34 g NH_3 gives = 106 g Na_2 CO_3 Thus, 1000 ...

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Standard XI

Chemistry

Stoichiometric Calculations

In the Solvay...

Question

In the Solvay process for producing sodium carbonate $(N a_{2} C O_{3})$ , the following reactions occur in sequence.
$N H_{3} + C O_{2} + H_{2} O \to N H_{4} H C O_{3}$
$N H_{4} H C O_{3} + N a C l \to N H_{4} C l + N a H C O_{3}$
$2 N a H C O_{3} Δ - \to N a_{2} C O_{3} + H_{2} O + C O_{2}$
How much of $N a_{2} C O_{3}$ would be produced per kg of $N H_{3}$ used if the process were 100% efficient?

3.12 kg

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1.00 kg

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2.00 kg

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0.56 kg

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Solution

The correct option is A 3.12 kg
Based on stoichiometry,
1 mol $N a_{2} C O_{3}$ is obtained from 2 mol $N H_{3}$

$106 g N a_{2} C O_{3}$ is from $= 2 \times 17 g N H_{3}$
$34 g N H_{3}$ gives = 106 g $N a_{2} C O_{3}$
Thus, $1000 g N H_{3}$ gives $= \frac{106 \times 1000}{34} g N a_{2} C O_{3}$
$= 3118 g N a_{2} C O_{3}$
$= 3.118 k g N a_{2} C O_{3}$

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Similar questions

Q. In the Solvay process for producing sodium carbonate

(N a_{2} C O_{3})

, the following reactions occur in sequence.

N H_{3} + C O_{2} + H_{2} O \to N H_{4} H C O_{3}

N H_{4} H C O_{3} + N a C l \to N H_{4} C l + N a H C O_{3}

2 N a H C O_{3} Δ - \to N a_{2} C O_{3} + H_{2} O + C O_{2}

How much of

N a_{2} C O_{3}

would be produced per kg of

N H_{3}

used if the process were 100% efficient?

Q. In the above reaction if

A

N H_{4} C l

and

D

C O_{2}

then

B

C

respectively are :

(A)

+ N a O H \to N a C l + N H_{3} + H_{2} O

N H_{3} + C O_{2} + H_{2} O \to (B)

(B)

+ N a C l \to (C) + N H_{4} C l

(C)

\to N a_{2} C O_{3} + H_{2} O + (D)

Q. Identify

X

in the following reaction.

N a C l + H_{2} O + C O_{2} + N H_{3}

\to

N H_{4} C l + X

.
Identify

X

from the following options.

Q. The chemical reactions involved in the ammonia soda process are represented as follows:

2 N a C l + C a C O_{3} \to N a_{2} C O_{3} + C a C l_{2}

In the following reactions,

C a C O_{3} Δ - \to [A] + [B]

N a C l + N H_{3} + [B] + H_{2} O \to [C] + [D]

2 [C] \to N a_{2} C O_{3} + H_{2} O + [B]

Identify A to D:

Q. In the manufacture of sodium carbonate, the following reactions are involved:

(A) Δ - \to (B) + {CO}_{2}

(B) + H_{2} O \to (C) N H_{4} C l - --- \to (D)

(E) + {CO}_{2} \to (F)

(F) + NaCl \to G H e a t - -- \to {Na}_{2} {CO}_{3} + {CO}_{2} + H_{2} O

{(D) is a gas which is soluble in H}_{2} O

The name of the process is:

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In the Solvay process for producing sodium carbonate (Na2CO3), the following reactions occur in sequence. NH3+CO2+H2O→NH4HCO3 NH4HCO3+NaCl→NH4Cl+NaHCO3 2NaHCO3Δ−→Na2CO3+H2O+CO2 How much of Na2CO3 would be produced per kg of NH3 used if the process were 100% efficient?

The correct option is A 3.12 kgBased on stoichiometry, 1 mol Na2CO3 is obtained from 2 mol NH3 106 g Na2CO3 is from =2×17 g NH3 34 g NH3 gives = 106 g Na2CO3 Thus, 1000 g NH3 gives =106×100034g Na2CO3 =3118 g Na2CO3 =3.118 kg Na2CO3